Draw a Labelled Diagram of Stomata

ICSE Solutions for Class 10 Biology – Transpiration

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Short Questions

Question 1: Define transpiration.
Answer: Transpiration is a process in which backlog of water is lost in the form of vapours from the aerial parts of the constitute.

Question 2: Name the 3 types of transpiration.
Answer: (i) Stomatal transpiration.
(2) Lenticular transpiration.
(iii) Cuticular transpiration.

Question iii: What is meant by the term transpiration stream ?
Answer: A pulling forcefulness called suction, caused by the evaporation of water in a foliage draws a long, continuous column of h2o through the xylem from the root to the leaf. This is called the transpiration stream.

Question 4: Where are stomata generally found ?
Answer: Stomata are generally found on the epidermis of the leaf.

Question five: Country the functions of guard cells.
Answer: Guard cells regulate opening and closing of stomata thus, control gas substitution and transpiration.

Question vi: How does a stomata differ from a lenticel ?
Answer: Stomata present, on the leaf and open merely during the mean solar day while lenticel present on the stem of woody plants and open up at all the times.

Question 7: What are lenticels ? Where are they found ?
Answer: Lenticels are minute, permanent openings which may develop in the young stems of woody plants. Some water is lost continuously through the lenticular openings in the form of water vapour.

Question 8: (i) Proper name the organ in which baby-sit cells are located and mention the chief functions of these.
(ii) Requite the office of thick cuticle layer in desert plants.
Answer: (i) The guard cells are located in the leaves. These regulate the stomatal opening for transpiration and diffusion of gases and close in gild to reduce water transpiration.
(two) It lowers the charge per unit of transpiration thus conserving water.

Question 9: What is the advantage of wilting to a constitute ?
Respond: The stomata close and at that place is a general reduction in the loss of water by the leaves due to transpiration.

Question x: Briefly explain how the rate of transpiration is afflicted by:
(a) Intensity of light.
(b) Humidity of the atmosphere.
Answer: (a) Low-cal intensity: It increases or decreases the charge per unit of transpiration. In stiff light, the rate of transpiration is more considering stomata are wide open up. In dim low-cal or on a cloudy twenty-four hour period the stomata are partially closed reducing the rate of transpiration.
(b) Humidity of the temper: If the air outside is humid the rate of transpiration is reduced, since the outward improvidence of internal water vapour is afflicted.

Question 11: Describe any 3 weather condition which bear on transpiration.
Answer: The iii conditions which touch transpiration are the following :

1. Sunlight: In vivid sunlight, the stomata remains fully open and transpiration takes identify through the stomatal pores. At night stomata remains closed, and then transpiration is reduced.
2. Wind: If the Wind velocity is high, transpiration becomes rapid considering the h2o vapour is carried away before the air effectually the leaf becomes saturated.
3. Available h2o: If available water in the soil is depression, the transpiration is low and the leaves may fifty-fifty begin to wilt.

Question 12: What are the advantages of transpiration to the plant ?
Answer: (i) It results in ascent of sap past creating a suction force.
(2) Information technology results in cooling of the plant in summertime.
(three) It helps in distribution of water to all parts of the plants.
(iv) Information technology helps in elimination of excess of water absorbed by the roots.

Question 13: What are the disadvantages of transpiration ?
Respond: (i) Some plants volition dice due to excessive h2o loss by transpiration.
(ii) Due to high rate of transpiration plant suffer from loss of turgidity.

Question 14: "A college charge per unit of transpiration is recorded on a windy day rather than on a calm mean solar day." Explicate.
Reply: Wind causes faster movement of air and remove the moist air and faster evaporation of water and therefore college rate of transpiration.

Question 15: Explain the human relationship between transpiration through the aerial parts and absorption by the root hairs.
Answer: The loss of water due to transpiration tends to lower the concentration of water in the jail cell sap. Thus, the root hair with its semi-permeable membrane and hypertonic cell sap plant an osmotic system with the water available in the soil surrounding the root pilus. This is how the 2 processes are interrelated.

Question sixteen: Describe an experiment to show that transpiration occurs more from the nether surface of dorsiventral leaves.
Answer: Two equal pieces of cobalt chloride newspaper are stale and placed one on the upper surface and the other on the lower surface of dorsiventral leaves. They are firmly held in place by pieces of cellotapes or glass slides. After a few minutes the cohalt chloride newspaper shows change in colour from blue to pinkish. The fourth dimension taken for the cobalt chloride newspaper on the upper surface of the leafage to plough pink is much longer than for the under surface. Thus, it proves that the charge per unit of transpiration is greater from the under surface of dorsiventral leaves.

Requite Reasons

Question 1: Transplanting of seedlings to flowerbed in the evening is better than doing then in the forenoon.
Respond: During solar day time transpiration rate is very high. Every bit a upshot to excessive transpiration and the seedling will wilt and ultimately die. However in the evening, transpiration rate is very tiresome and the seedling will exist able to retain the water absorbed from the soil and as a result of this they will remain transplanted.

Question 2: Country plants die if their foots remain water logged.
Respond: Older portions of the root do not have root hairs. They are covered with a protective layer of dead calls having tiny openings called lenticels. Through these lenticels, gaseous exchange occurs between the soil and inner living cells. If the roots of land plants remain waterlogged, and so lenticels volition not be able to practise gaseous exchange and as a issue of this plants will dice.

Question iii: Young plants volition an a hot sunny day.
Reply: On a hot sunny day, the rate of transpiration exceeds the rate of h2o assimilation by roots. As a upshot of this leaves collapse and establish wilts.

Question 4: Plants absorb more water than their requirement.
Answer: The plants absorb much more water than their requirement because:
(a) They require more than mineral salts for their growth and minerals are present in very small quantity in h2o
(b) About of the h2o is lost through transpiration. Therefore, to forestall wilting they require backlog of water.

Question 5: Balsam plants wilt during midday even if the soil is well watered.
Respond: Transpiration rate in such plants is very high during mid day and exceeds the water absorption rate of the roots. So more than water is lost than absorbed. This water deficiency in cells crusade them to loose turgidity and the plants wilt.

Question vi: Why do plants absorb more water than what is required by them ?
Answer: Plants absorb more than water than required because minerals are nowadays in extremely pocket-sized quantity in captivated water. To obtain a continuous supply of minerals it has to absorb big quantity of water.

Question vii: Forest bring in the rain, transpiration is the crusade. Explain why.
Answer: When water is lost by evaporation (transpiration) heat energy is taken upwardly from the plant body to vapourize the water, here the h2o is speedily taken up by the roots and again released through the leaves past transpiration. In the air higher up, the moisture forms clouds and soon falls equally rain.

Question 8: Why do some herbaceous plants show wilting of leaves during mid-day which again recover in the evening ?
Reply: During mid-solar day the charge per unit of transpiration is maximum. During this time, in some herbaceous plants, the rate of transpiration exceeds the corporeality of h2o absorbed. Thus, the leaves loss its turgid land and prove wilting.

Question ix: Guard cells are minor in size and are kidney shaped in outline.
Answer: Because of their small size, baby-sit cells are rapidly influenced by turgor changes. Because of their kidney shaped outline, they remain joined at their ends. This concave-convex curvature of the ii guard cells can be varied easily and this further facilitates the stomatal pore to open and close hands.

Differentiate

Question 1:Transpiration and Guttation.
Reply:

Transpiration	Guttation
(i) It is regulated by baby-sit cells	It is due to root pressure.
(ii) Information technology occurs at day fourth dimension.	It occurs at dark.
(iii) H2o escapes through stomata and lenticels.	Water escapes through hydathodes only.
(iv) Water escapes in the form of water vapour.	Water escapes from the hydathodes on the margin of the leaves in the form of water droplets.

Question two:Transpiration and Evaporation.
Respond:

Transpiration	Evaporation
Loss of h2o in the grade of vapour from aerial parts of the plant.	Loss of h2o from the surface of the water bodies in the grade of vapour.
It is a vital and partly a physical process controlled by both internal and external factors.	It is a physical change controlled past the temperature and humidity of the temper.
It is a slow procedure.	It is a fast process.

Question 3:Stomata and Lenticels.
Answer:

Stomata	Lenticels
(i) These are located on the lower surface of dicot leaves and both upper and lower surfaces of monocot leaves.	These are located on the stems of woody plants.
(two) They lose water vapour and process is termed stomatal transpiration.	They lose h2o vapour and process is called lenticular transpiration.

Question 4:Cuticular and Lenticular transpiration.
Reply:

Cuticular Transpiration	Lenticular Transpiration
It takes place through the thin cuticle covering the leaves of the plant.	Information technology takes place through the opening on the stems of woody plants, chosen lenticels.

Question 5:Transpiration and Translocation.
Answer:

Transpiration	Translocation
It is the loss of water in the form of h2o vapour from the aeriform organs of the plant.	It is the transfer of prepared nutrient to the different parts of the plant, including the storage organs.
Information technology occurs through stomata.	Information technology occurs through vascular tissues.

Question half dozen:Transpiration and Perspiration.
Respond:

Transpiration	Perspiration
(i) It takes place in plants.	It takes place in animals.
(ii) Only water vapour is removed.	Sweat containing urea, uric add and salts are removed with water.
(iii) Information technology takes identify through the leaves and stem and through the stomata and lenticels.	It takes place through the skin. It takes place through the sweat pores of the sweat glands.

Question 7:Stomata and Hydathodes.
Answer:

Stomata	Hydathodes
Stomata pass out water in the form of vapours.	Hydathodes send out water in the form of droplets.

Question 8:Guttation and Haemorrhage.
Reply:

Guttation	Haemorrhage
It is the process in which water droplets oozes out from the hydathodes present at the tip and margins of leaves.	It is the process in which institute sap oozes out through injured or cut ends of the plant.

Question ix:Cobalt chloride newspaper and Goat's bladder.
Answer:

Cobalt Chloride Paper	Goat's Float
It is used for the process of transpiration to check the presence of water.	It is used for the process of osmosis as semi- permeable membrane.

Diagram Based Questions

Question one: The diagram below represents a structure institute in a leaf.

Written report the same and answer the questions that follow:
(i) Proper noun the pis labeled A and B.
(two) What is the biological term for the above construction?
(iii) What is the function of the part labeled A?
(iv) Mention two structural features of A, which help in the part mentioned in (iii) in a higher place.
(v) Where is this construction likely to be plant in a foliage?
(vi) The above structure helps in the process of transpiration. Explicate the term transpiration.
(seven) How many other cells are found surrounding this structure as seen in the diagram?
Answer: (i) A—Guard cell B—Stoma.
(ii) Stomatal apparatus.
(iii) Regulates opening & dosing of Stomata.
(iv) Gives rigidity and protection to the cell.
(v) On the epidermis of leaf.
(vi) Transpiration is the loss of water equally water vapours from the aeriform parts of the plant.
(vii) Five.

Question 2: The effigy below represents the vertical section of a leaf:

(i) Name the parts labeled 1 to five.
(ii) What do the two arrows (dotted and solid) indicate in the solar day fourth dimension and at night ?
(iii) Could you add together one more pointer in the figure ? If yeah, what for ?
(four) How many leafage veins take been shown in this section ?
Answer: (i) 1. Cuticle, 2. Upper epidermis, iii. Palisade tissue, four. Spongy parenchyma, 5. Baby-sit prison cell of stoma.
(ii) In the day time dotted arrow shows the path of CO₂ while solid arrow shows the path of oxygen. A nighttime dotted arrow shows the path of oxygen while solid pointer shows the path of CO_ii:
(3) Yes, nosotros tin can add together one more arrow in the effigy to show the loss of h2o during transpiration.
(iv) Just one leaf vein has been shown in this section.

Question 3: Given beneath are the diagrams of a sure structure in plants in two conditions.

(i) Proper name the structure shown.
(ii) Proper noun the parts numbered 1-5.
(iii) What is the almost credible difference betwixt A and B in the structure shown ?
(iv) Describe the mechanism which brings well-nigh the modify in the construction depicted in A and B.
Reply: (i) Stomata surrounded by epidermal cells.
(ii) i. Chloroplast, 2. Inner wall of baby-sit cells, 3. Nucleus, iv. Guard cells, v. Stoma.
(3) The stoma is open in A and is almost airtight in B.
(4) The opening and dosing mechanism of stomata is regulated by the corporeality of h2o and solutes present in the baby-sit cells. The guard cells have a thick inner wall facing the opening and a thin outer wall on the opposite side; their cytoplasm contains chloroplasts. During the day guard cells begin photosynthesis and the carbohydrate produced during the process increases the osmotic pressure which draws in h2o from the adjoining cells. Hence, the guard cells become turgid and bulge outward due to their thin outer wall, thus widening the stomatal opening lying in betwixt (Fig. A). As the stomata open, the diffusion of gases in and out begins for fulfilling the need for photosynthesis and for assuasive transpiration. If for any reason the water content of the leaf is falling brusque, the guard cells fail to remain turgid, they turn flaccid or lose turgidity, thereby closing the stomatal opening (Fig. B) and the transpiration stops.

Question iv: Given beneath is an experimental set to study a particular procedure :

(i) Name the procedure existence studied.
(2) Explicate the process named in (i) in a higher place.
(iii) Why is the pot covered with a plastic canvas ?
(iv) Mention one way in which this procedure is beneficial to the constitute.
(5) Suggest a suitable control for this experiment.
Respond: (i) Transpiration.
(ii) It is procedure in which water in the course of vapours are released from the aeriform parts similar leaves and soft stems of the plant.
(iii) The plastic sheet will not allow the moisture of the mud of the pot to come out and touch on the effect.
(iv) It helps in ascent of sap in the plant.
(v) A similar apparatus is set without the potted plant. In its place a same plastic bag, with its mouth tied, is kept in the bong jar. No water drops will announced in the bell jar.

Question five: The figure given beneath represents an experimental set up upward with a weighing machine to demonstrate a particular process in plants. The experimental ready up was placed in vivid sunlight. Study the diagram and respond the following questions:

(i) Name the procedure intended for study.
(ii) Ascertain the above mentioned process.
(three) When the weight of the test tube (A & B) is taken earlier and afterward thee experiment, what is observed ? Give reasons to justify your observation in A & B.
(iv) What is the purpose of keeping the exam tube B in the experimental fix?
Respond: (i) Transpiration.
(ii) It is the release of water vapours from the aerial parts of the institute.
(3) Weight of test tube A will decrease afterward the experiment because water will be lost from it through the leaves by transpiration,. Weight of test tube B will remain same later on the experiment because water will non exist lost by transpiration as there is no plant in and nor past evaporation equally oil is spread over it, which volition non allow evaporation.
(iv) It is a control experiment where the purpose of using examination tube B is to compare the level of h2o in both examination tubes.

Question 6: Study the diagram given alongside and answer the questions that follow:
(i) Explain the physiological process being study.
(ii) What will be the observations in the two examination-tubes after virtually two-three days?
(iii) Give a reason for your answer in (ii) above.
(iv) Why is the surface of water covered with oil.
(v) State the purpose of setting upward test tube B.
Respond: (i) Transpiration: Loss of water as h2o vapour from aerial parts of the constitute.
(ii) After 2-three days the level of h2o falls in exam-tube A while it remains abiding in test tube B.
(three) The autumn in the level of water in test-tube A due to the absorption of water past the roots.
(iv) The oil has been put in each examination-tube to foreclose the loss of h2o by evaporation.
(v) The purpose of setting up exam-tube B is to bear witness that in the absence of plant, there is no change in the level of h2o.

Question 7: Study the diagram given below and respond the questions that follows:

(i) Name the process existence studied in the higher up experiment.
(ii) Explain the process mentioned in (i) in a higher place.
(three) Why is oil placed over water?
Respond: (i) Transpiration
(2) It is the process past which plants lose h2o as vapours through the aerial parts.
(iii) To prevent evaporation of water from the exam tube.
(iv) one. In bright sunlight the level of water decreases chop-chop.
two. In humid conditions level of water does non decrease for a long fourth dimension.
3. On windy day level of water decreases very rapidly.
(v) ane. The number of stomata may be reduced.
2. leaves may become narrow.
iii. A thick layer of cuticle on the leaf surface help to subtract transpiration

Question 8: Given below is the diagram of an experimental set up to written report the process of transpiration in plants. Study the same and and then answer the questions that follow:

(i) What is the colour of dry out cobalt chloride newspaper?
(ii) Is the experimental leafage a monocot or a dicot? Give a reason to back up your respond.
(three) Why axe drinking glass slides placed over the dry out cobalt chloride papers?
(iv) Afterwards nigh half an hr what modify, if whatever, would yous expect to find in the cobalt chloride paper placed on the dorsal and ventral sides of the leaf? Give a reason to support your answer.
(5) Define the term 'transpiration'.
Answer: (i) The colour of dry cobalt chloride paper is blue.
(ii) Dicot foliage. Information technology has reticulate venation.
(three) To prevent water vapour of the air from interfering the experiment. .
(4) The cobalt chloride paper placed on the lower surface of the leaf volition testify more pink dots every bit there are more than stomata. The upper surface has less stomata than the lower surface.
(v) Loss of h2o every bit h2o vapour from the aerial parts of the institute.

Question 9: The apparatus shown here is Girreau's poto-meter designed to demonstrate diff transpiration from the two surfaces of a dorsiventral leaf. Before keeping the leaf in between the cups, anhydrous calcium chloride (CaCl₂) contained in two small vials were weighed and placed in both the cups. The ends of the cups were closed with corks through which two mercury manometers were continued. After a few hours, CaCl₂ vials were taken out and
weighed again.

(i) What is the purpose of keeping CaCl₂ vials inside the cup?
(ii) Afterward a few hours, the CaCl_ii vials were taken out and weighed over again. Volition you expect whatever departure in weight ? If so, give reasons.
(iii) What was the purpose of using a mano-meter?
(iv) What practice you lot mean by transpiration?
Reply: (i) The CaCl_two vials are kept within the cup to absorb water.
(two) After few hours, the weight of the CaCl_two vials will increase considering they volition blot the water which is transpired by the leaf of the plant.
(three) Manometers are used to indicate the diff transpiration from two surfaces of a dorsiveritral leaf by showing deviation in rise in their mercury levels.
(iv) Transpiration is the loss of water in the course of water vapour from the aerial parts of the living plants.

Question 10: The following diagram is fix up to demonstrate an experiment.

5 plants A, B, C, D and E were placed in a chalice containing h2o. The h2o in each chalice was covered with a layer of oil. The leaves were removed from plant D in plant B, upper surfaces of all the leaves were covered with Vaseline, in plant C the lower surfaces of all the leaves were covered with Vaseline and institute E was exposed to potent light. The beakers were and so left for few hours and at the finish of the experimental period, weights of each beaker were
taken.
Write the right reply out of the v bachelor choices given under each question:
I. In which beaker would you await the greatest decrease in weight?
(i) A (ii) B (iii) C (4) D (v) Due east
II. In which chalice the modify of weight would be minimum?
(i) A (ii) B (3) C (iv) D (five) Due east
III. Which plant would remain healthy for a longer period of time?
(i) A (ii) B (iii) C (iv) D (five) Eastward
IV. In this experiment which plant can be considered equally the uncontrolled one?
(I) A (two) B (three) C (four) D (v) Due east
V. The difference of weight would b maximum betwixt:
(i) A and B (two) A and C (iii) A and D (4) A and E (5) D and E
Answer: I. (v) E,  II. (four) D,  Three. (i) A,  4. (i) A,  V. (five) D and Due east.

Question xi: Given below is an apparatus used to written report a detail process in plants. Study the same and ansvver the questions that follow :
(i) Name the appliance.
(two) Mention one limitation of this appliance.
(iii) Which phenomenon is studied with the help of this apparatus?
(iv) What is the function of the part marked 'reservoir'?
(five) What is the office of the air bubble in the experiment?
Answer: (i) Garreau's Potorneter.
(ii) The capillary tube should be properly dipped into the water.
(iii) Transpiration.
(iv) Information technology is used to suit the position of air bubble in graduated capillary tube.
(5) The movement of air bubble in graduated tube in a infinitesimal gives the rate of transpiration.

Sketch and Label the Diagram

Question ane: Draw a labeled diagram of the stomatal apparatus and label the following in it: Stoma, Baby-sit cells, Chloroplast, Epidermal cells and Cell wall.
Answer:

Question 2: Draw a slap-up diagram of the stomatal apparatus found in the epidermis of leaves and label the Stoma, Guard cells, Chloroplast, Epidermal Cells, cell wall and Nucleus.
Respond:

Explain the Terms

Question:
one. Transpiration
ii. Cuticular transpiration
iii. Lenticular
4. Stomatal transpiration
5. Guttation
6. Bleeding
7. Lenticel
8. Hydathode
9. Wilting
Answer: 1. Transpiration is defined every bit the loss of water vapour by the plant. It may accept place from any role of the constitute body.
2. Cuticular transpiration takes place through the cuticle (waxy layer) covering the leaves.
three. Lenticular transpiration takes place through the small-scale openings in the corky tissue covering the stem.
4. Stomatal transpiration takes identify through the stomata on the leaves. .
5. Guttation is defined equally the loss of water in the form of h2o droplets from the leaves of intact plants. It is likewise called exudation.
half-dozen. Bleeding is the flow of the plant sap at the sites of injury or cuts.
vii. Lenticel: A pore in the periderm of a woody stalk. It acts as an organ of gaseous exchange.
viii. Hydathode: A water secreting gland found on the edges and tips of leaves of many plants.
9. Wilting: The collapse of leaves due to unfavourable water relations. It may be due to excessive transpiration every bit compared to absorption of h2o by roots. Information technology may also be due to blocking of the xylem elements, pathogens or parasites.

Name the Following

Question:
i. The procedure of getting rid of backlog water in the form of water vapour through the stomata.
two. Season in which transpiration rate is the highest.
3. Holes present on the surface of the stems and twigs for transpiration.
four. Potometer is an instrument for measuring the charge per unit of the well-nigh transpiration in a herbaceous institute like Balsam occurs through which function.
5. Plants in which lenticular transpiration.
half dozen. A plant having sunken stomata.
7. Loss of water as aerosol through leaves of an intact plant.
8. The structures through which guttation occurs.
nine. The escape of plant sap from the ruptured or cut surfaces of the establish due to root pressure.
Answer:
1. Transpiration
two. Summertime
3. Lenticels
4. Stomata
v. Woody copse
6. Xerophyte
vii. Guttation
eight. Hydathodes
9. Bleeding

Give Technical Terms

Question:
1. Loss of water from the aerial parts of a plant.
2. Opening establish on the under surface of dorsiventral leaf.
iii. Which side of the leafage has more than stomata ?
iv. When cobalt chloride paper is placed on lower and upper surface of the foliage, the paper of which side becomes more pinkish ?
5. The substances which check the rate of transpiration.
6. The paper which is used to show loss of h2o through stoma of a leaf.
7. A chemic used to preclude excessive transpiration in plants.
viii. Master function of lenticel.
ix. The apparatus used to compare the rate of transpiration in cutting shoot.
10. The process by which excess of water is forced out straight from the tips of veins in the leafage.
Answer:
i. Transpiration
2. Stomata
3. Lower side
4. Lower side
5. Anti-transpirants
vi. Cobalt chloride paper
7. Silicon emulsions/phenyl mercuric acetate
8. Commutation of gases and transpiration
9. Darwin's potometer
x. Guttation

Fill in the Blanks

Complete the following sentences with appropriate words :
one. Plants get absurd as a result of Transpiration.
two. Transpiration is the loss of water In the form of water vapour from the leaves of the plant.
3. Transpiration usually takes identify in the presence of Sunlight.
4. 95% of the full transpiration takes place through Stomata.
5. In Nerium, the stomata are nowadays in Sunken pits.
half dozen. Openings found on the under surface of the dorsiventral foliage are Stomata.
vii. The leaves of the Xerophytic plants have cuticular wax.
8. Guttation takes place more often than not at Night.

True & Imitation

Mention, if the following statements are True or False. If false rewrite the incorrect statement in its correct class:
ane. Transpiration is a physiological process. (True)
ii. Root hairs are the extensions of the outer epidermal cells of the root. (True)
three. More than transpiration occurs from the upper surface of a leaf. (Imitation, More than transpiration occurs from the under surface of a leaf.)
4. Transpiration takes identify but in green plants. (True)
5. The pH of the guard cells increases during 24-hour interval time. (True)
6. Evaporation is a physiological procedure. (Imitation, Evaporation is a physical procedure.)
seven. Potometer is an instrument, used for measuring the rate of transpiration. (True)
8. Depression humidity in the atmosphere results decrease in the rate of transpiration. (False, High humidity in the atmosphere results decrease in the charge per unit of transpiration.)
ix. Calcium chloride paper is used to demonstrate transpiration. (False, Cobalt chloride newspaper is used to demonstrate transpiration.)
10. Moist cobalt chloride paper is blue in colour. (False, Moist cobalt chloride paper turns pink in colour.)
eleven. Guttation occurs through stomata. (Imitation, Information technology occurs through hydathodes.)

State the Location

Proper noun	Location
Stomata	Present in the epidermis of green, aeriform parts of plants, especially the leaves.
Lenticels	Present in the bawl of woody plants.
Cuticle	It is a non-cellular waxy layer secreted by the epidermis and it surrounds the epidermis.
Hydathodes	Present on the edges and tips of leaves of many plants.
Baby-sit cells	Present in the stoma (plural of stoma is stomata).

State the Function

Write the functional action of the post-obit structures:

Proper name	Function
Stomata	(a) Loss of water vapours due to transpiration. (b) Gaseous substitution.
Lenticels	They aid in gaseous exchange.
Cuticle	It protects the surface and reduces water loss.
Hydathodes	Plants secrete excess of water through hydathodes when temper is very humid and transpiration process cannot occur.
Guard cells	(a) Command the size of the discontinuity. (b) As well help in photosynthesis every bit they contain chloroplasts too.

Choose the Odd One Out

1. Transpiration, Photosynthesis, Phagocytosis, Guttation. (Phagocytosis)
two. Cuficular transpiration, Lenticular transpiration, Stomatal transpiration, Gutation. (Guttation)
3. Stomata, Cuticle, Lenticels, Hydathodes. (Hydathodes)

Multiple Choice Questions

ane. In the mechanism of opening and endmost of stomata, the of import factor is :
(a) The presence of chloroplast in the guard cells
(b) The turgid and flaccid state of the baby-sit cells
(c) The poly peptide content of the cells
(d) The starch content of the cells

two. Stomata open during solar day and close at nighttime because :
(a) Photosynthesis occurs during 24-hour interval time only
(b) Enzymes convert starch into carbohydrate at elevated pH in night
(c) Loss of sugar increases osmotic concentration of the cell sap
(d) Loss of starch in day fourth dimension raises OP of subsidiary cells

3. In hot summer days, constitute cooling is due to :
(a) Loss of h2o vapours from leaves (b) Transport of water in plant
(c) Loss of lkjuid water (d) Loss of h2o from entire plant

4. If the rate of transpiration becomes more than than the rate of photosynthesis, plants will:
(a) Keep to live, but volition not be able to store nutrient
(b) Be killed instantly
(c) Grow more vigorously considering more energy will exist available .
(d) End growing and gradually dice of starvation

v. Transpiration is very depression during storms due to :
(a) Presence of moisture in the wind
(b) Low temperature during storms
(c) High velocity of current of air
(d) None of the above

half dozen. Transpiration pull volition be maximum under which of the post-obit conditions ?
(a) Open stomata, dry out atmosphere and moist soil
(b) Open stomata, loftier humid atmosphere and well irrigated soil
(c) Open up stomata, high humid atmosphere and dry soil
(d) Close stomata, dry atmosphere and dry soil

7. Plants lose water by guttation when:
(a) Rate of transpiration is high
(b) Soil is wet and the atmosphere is humid
(c) Soil is dry out and atmosphere is dry
(d) Soil is moisture and atmosphere is dry

8. Guttation is the emptying of excess of water from plants through :
(a) Stomata (b) Hydathodes
(c) Lenticels (d) Wounds

Match the Column

Column 'Ii' is a list of items related to ideas in Column 'I'. Match the term in Column 'II' with the suitable idea given in Column 'I'.

Column I	Column Two
(i) Transpiration	(a) Cacti plants
(ii) Movement of water	(b) Stomata
(iii) Guttation	(c) Maize plant
(4) Low rate of transpiration	(d)Xylem
(v) Loftier rate of transpiration	(e) Hydathodes

Answer:(i) (b)   (ii) (d)   (iii) (due east)   (iv) (a)   (five) (c)

For More Resources

• ICSE Solutions Physics
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